False.
For S to be a subspace it needs to satisfy a few requirements that it doesn't. Three examples:
- We must have that if x and y are in S, then x+y is in S. But clearly (1,1) and (0,1) are in S, but their sum (1,2) is not in S.
- Similarly, we need that for every t in R and x in S, t*x is in S. But (1,1) is in S and 2*(1,1)=(2,2) is not.
- S does not contain the zero vector, which is another requirement for a subspace.
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